File Upload via iControl REST

Code :

def _upload(host, creds, fp):

    chunk_size = 512 * 1024
    headers = {
        'Content-Type': 'application/octet-stream'
    }
    fileobj = open(fp, 'rb')
    filename = os.path.basename(fp)
    if os.path.splitext(filename)[-1] == '.iso':
        uri = 'https://%s/mgmt/cm/autodeploy/software-image-uploads/%s' % (host, filename)
    else:
        uri = 'https://%s/mgmt/shared/file-transfer/uploads/%s' % (host, filename)

    requests.packages.urllib3.disable_warnings()
    size = os.path.getsize(fp)

    start = 0

    while True:
        file_slice = fileobj.read(chunk_size)
        if not file_slice:
            break

        current_bytes = len(file_slice)
        if current_bytes < chunk_size:
            end = size
        else:
            end = start + current_bytes

        content_range = "%s-%s/%s" % (start, end - 1, size)
        headers['Content-Range'] = content_range
        requests.post(uri,
                      auth=creds,
                      data=file_slice,
                      headers=headers,
                      verify=False)

        start += current_bytes

if __name__ == "__main__":
    import os, requests, argparse, getpass

    parser = argparse.ArgumentParser(description='Upload File to BIG-IP')

    parser.add_argument("host", help='BIG-IP IP or Hostname', )
    parser.add_argument("username", help='BIG-IP Username')
    parser.add_argument("filepath", help='Source Filename with Absolute Path')
    args = vars(parser.parse_args())

    hostname = args['host']
    username = args['username']
    filepath = args['filepath']

    print "%s, enter your password: " % args['username'],
    password = getpass.getpass()

    _upload(hostname, (username, password), filepath)

Tested this on version:

12.0
Published Nov 05, 2015
Version 1.0

Was this article helpful?

16 Comments