File Upload via iControl REST

Code : def _upload(host, creds, fp): chunk_size = 512 * 1024 headers = { 'Content-Type': 'application/octet-stream' } fileobj = open(fp, 'rb') filename = os.path.basenam...
Published Nov 05, 2015
Version 1.0
iControlREST
python
JRahm's avatar
JRahm
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Apr 25, 2016
ok, so change that "will not work" to "is not supported" before 12.0 :) Nice work guys.