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File Upload via iControl REST

Code : def _upload(host, creds, fp): chunk_size = 512 * 1024 headers = { 'Content-Type': 'application/octet-stream' } fileobj = open(fp, 'rb') filename = os.path.basenam...
Published Nov 05, 2015
Version 1.0
iControlREST
python
JRahm's avatar
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Christ Follower, Husband, Father, Technologist. I love community and I especially love THIS community. My background is networking, but I've dabbled in all the F5 iStuff, I'm a recovering Perl guy, and am very much a python enthusiast. Learning alongside all of you in this accelerating industry toward modern apps and architectures.
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JRahm's avatar
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Christ Follower, Husband, Father, Technologist. I love community and I especially love THIS community. My background is networking, but I've dabbled in all the F5 iStuff, I'm a recovering Perl guy, and am very much a python enthusiast. Learning alongside all of you in this accelerating industry toward modern apps and architectures.
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Maverick_80689
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Mar 18, 2016
Thanks Jason, please ignore my previous comment. It works with version 11.5.1, just needed to adjust permissions on the destination folder.