create a method parameter for protocol type

just to be clear, it should look like this :

 

 

proto = v.typefactory.create('Common.ProtocolType')

 

vs_def.protocol = proto.PROTOCOL_TCP

 

It would seem I am thinking about this all wrong. So I decided to do this in a better way and just test the paramter string that I use for protocol and based on the comparison I will set it accordingly. So something like this will work fine and I will have each type defined per the icontrol SDK. I am not a big fan of if statements but since python does not appear to have a "case" as in other languages and this is a small amount of comparisons.... it will do.. This gets away from the trying to concatenate a string with a non-string object, which will not work. Anyway it may not be the best way but it seems to work ok so far..

 

 

 

p_type is a parameter to a web service call

 

 

 

proto = v.typefactory.create('Common.ProtocolType')

 

 

if p_type == "tcp":

 

p= proto.PROTOCOL_TCP

 

 

vs_def.protocol = p

 

 

 

ok yeah that is cleaner way... Awesome thanks for your help!! That saves me from having to do the comparison logic with if statements...

 

 

 

Andy