Forum Discussion
andy_12_5042
Nimbostratus
Nimbostratuscreate a method parameter for protocol type
Is there a way I can properly do this below? I am trying to allow the protocol type to be defined in the call itself via a method. However, my lack of Python or in depth programming is killing me with this simple issue. What is the correct way to do this ?
vs_def.protocol = proto + "." + prot_type
TypeError: unsupported operand type(s) for +: 'instance' and 'str'
andy_12_5042just to be clear, it should look like this :
proto = v.typefactory.create('Common.ProtocolType')
vs_def.protocol = proto.PROTOCOL_TCP- andy_12_5042It would seem I am thinking about this all wrong. So I decided to do this in a better way and just test the paramter string that I use for protocol and based on the comparison I will set it accordingly. So something like this will work fine and I will have each type defined per the icontrol SDK. I am not a big fan of if statements but since python does not appear to have a "case" as in other languages and this is a small amount of comparisons.... it will do.. This gets away from the trying to concatenate a string with a non-string object, which will not work. Anyway it may not be the best way but it seems to work ok so far..
p_type is a parameter to a web service call
proto = v.typefactory.create('Common.ProtocolType')
if p_type == "tcp":
p= proto.PROTOCOL_TCP
vs_def.protocol = p - andy_12_5042ok yeah that is cleaner way... Awesome thanks for your help!! That saves me from having to do the comparison logic with if statements...
Andy