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Eric_Frankenfie's avatar
Eric_Frankenfie
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Oct 07, 2013

URI Rewrite

I have a developer who is working a new version of an application and they would like to perform the following URI rewrite on the F5 so they don't have to deploy duplicate code to 100+ virtual directories:

 

www.xyz.com/vendorName?whatever=1 to www.xyz.com?vendorName&whatever=1

 

Rather than maintaining a data group with each vendorName is it possible to replace '/vendorName?' with '?vendorName&' dynamically where vendorName will be a variable of any length?

 

application delivery
devops
iRules
uri rewriting
  • Joe_Pruitt's avatar
    Joe_Pruitt
    Oct 07, 2013

    Assuming you know the vendor name variable, you can do something like this:

    set vendor "vendorName";   assign from header or some other input
if { [HTTP::uri] starts_with "/${vendor}?" } {
  HTTP::uri [string map [list "/${vendor}?" "?${vendor}&"] [HTTP::uri]]
}

    If you want to look for all patterns and of "/?" and replace it, you can do so with something like this

    if { ([HTTP::uri] starts_with "/") && ([HTTP::uri] contains "?") } {
   Find the index of the "?" character
  set idx [string first "?" [HTTP::uri]]
   extract the string from index 1 up to the character before the "?"
  set site [string range [HTTP::uri] 1 [expr $idx - 1]]
   Modify the URI with the string replacement.
  HTTP::uri [string map [list "/${site}?" "?${site}&"] [HTTP::uri]]
}

    Keep in mind that this isn't bulletproof. So make sure the logic fits for all of your URLs.

    -Joe

  • Joe_Pruitt's avatar
    Joe_Pruitt
    Oct 07, 2013

    Here's another option

    if { ([HTTP::uri] starts_with "/") && ([HTTP::uri] contains "?") } {
   Find the index of the "?" character
  set idx [string first "?" [HTTP::uri]]
   replace the first character with "?" and the idx'th character with "&"
  HTTP::uri [string replace [string replace [HTTP::uri] 0 0 "?"] $idx $idx "&"]
}

    Have fun!

    -Joe