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MW1's avatar
MW1
Icon for Cirrus rankCirrus
Sep 13, 2010

SSL TPS verus SSL connections

All,

 

can anyone explain (or point me to a link with an explanation) SSL TPS versus SSL connections. I've been asked to provide peak & average SSL TPS more accurately than the inbuilt F5 graph. While looking for a way to find the peak usage I saw the command:

 

 

'bigpipe ssl stats' & noticed that the client side conn & native conn figure (both max and current) is far higher than the SSL TPS in the graph. From my understanding, which I now take as incorrect, each SSL connection would equal one SSL TPS.

 

 

Can anyone clear up my confusion on SSL TPS?

 

 

thanks

 

Matt

 

management
monitoring

2 Replies

  • JRahm's avatar
    JRahm
    Icon for Admin rankAdmin
    Sep 13, 2010
    Check out this thread: http://devcentral.f5.com/Forums/tabid/1082223/asg/44/showtab/groupforums/afv/topic/aff/32/aft/1171564/Default.aspx Click Here

     

     

    A more general but very informative treatise from Lori's blog: http://devcentral.f5.com/weblogs/macvittie/archive/2010/02/03/wils-ssl-tps-versus-http-tps-over-ssl.aspx Click Here
  • Hamish's avatar
    Hamish
    Icon for Cirrocumulus rankCirrocumulus
    Sep 13, 2010
    Connections != TPS.

     

     

    Connections == the number of concurrent connections.

     

    TPS == the number of NEW connections per second

     

     

    Be aware that the F5 counts TPS's very harshly... It's not actually licensed in transactions or connections per second. It's actually limited to TPS/100 per 10ms... So if you have a 100TPS license, you can only have 1 connection in a 10ms window. For a 1000TPS license you get 10 connections in a 10ms window. Any more will result in a license violation and a dropped connection (Even though you haven't gone over 100 transactions in a second).

     

     

    See soln 6475 for the details (http://support.f5.com/kb/en-us/solutions/public/6000/400/sol6475.html)

     

     

    A good rule of thumb is that the peak SSL TPS's is about 2x the 60 second average...

     

     

    H