Forum Discussion
THE_BLUE
Cirrostratus
CirrostratusParameter Value - Regular Expression
I want to restrict parameter value to accept date only, is below Regular Expression will work? ^([0-2][0-9]|(3)[0-1])(\/)(((0)[0-9])|((1)[0-2]))(\/)\d{4}$
I found this regex, fits in the 254 character limit and checks:
- valid dates
- if leap year, then 29.2. is also valid
(^(((0[1-9]|1[0-9]|2[0-8])[\/](0[1-9]|1[012]))|((29|30|31)[\/](0[13578]|1[02]))|((29|30)[\/](0[4,6,9]|11)))[\/](19|[2-9][0-9])\d\d$)|(^29[\/]02[\/](19|[2-9][0-9])(00|04|08|12|16|20|24|28|32|36|40|44|48|52|56|60|64|68|72|76|80|84|88|92|96)$)
THE_BLUECirrostratus
Cirrostratusi have modified the regex to ^([0-2][0-9]|(3)[0-1])(\/)(([0-9]|(0)[0-9])|((1)[0-2]))(\/)\d{4}$ , now it can accept both 29/3/2026 and 02/03/2022 but again can't detect non-existing date ex 31/2/2021
- Daniel_Wolf
MVP
I cannot judge which regex meets your requirements best. The usual syntax is dd/mm/yyyy.
Is it more important for you, to have a syntax that would catch dd/mm/yyyy and dd/m/yyyy?
Or is it it more important to filter out non-existing dates like 31/02/2022 and stick to the defacto standard of dd/mm/yyyy?
My regex foo is not strong enough to combine both requirements into one single regex.