Forum Discussion
How to enable 'Force Password Change' Field for batch processing
we need to create lots of different Local DB user and want to enable force password change for these user's first login. So,we create different Local db user by batch importing,including the field 'auto-unlock-interval' and 'lockout-threshold'.However,these batch created records all disabled the force password change. How to enable the field 'Force Password Change' Quickly and in batch for massive records?
1 Reply
- Seth_Cooper
Employee
Hi!
You can use ldbutil to manipulate records in the local db on the command line.
The following command lists the users and all the attributes. You can either provide your own list or use something like this to generate it.
[root@apm-host:Active:Standalone] config ldbutil --list uid="825" uname="test_user" instance="/Common/test" password="{SSHA}xxxxxxxx" user_groups="VPNUser" login_failures="0" passwd_expire="NULL" lockout_start="0" ttl="1421350493" dynamic_user="0" deleted="0" suspended="0" locked_out="0" change_passwd="0" last_modified="2015-07-01 13:27:52" first_name="Seth" last_name="Cooper" email="email@domain.com" FOUND_ROWS()="1" [root@apm-host:Active:Standalone] configHere we will parse the output using awk and sed to get just the username to be used in the next command.
[root@apm-host:Active:Standalone] config ldbutil --list | awk -F" " '{print $2}' | awk -F"=" '{print $2}' | sed s/\"//g | grep -v "^$" test_user [root@apm-host:Active:Standalone] configTo update the users record you will use the following command. Make sure to have the correct instance configured.
[root@apm-host:Active:Standalone] config ldbutil --update --uname="test_user" --instance="/Common/test" --change_passwd=1 [root@apm-host:Active:Standalone] configYou can use the previous commands in a for loop on the command line (simple example below)
for all in `command to create list` do command to run and use $all for the uname doneSo this would look like this for these commands:
for all in `ldbutil --list | awk -F" " '{print $2}' | awk -F"=" '{print $2}' | sed s/\"//g | grep -v "^$"` do ldbutil --update --uname="${all}" --instance="/Common/test" --change_passwd=1 doneI hope this helps! Please let me know if you have any additional questions.
-Seth
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