File Upload via iControl REST Code : def _upload(host, creds, fp): chunk_size = 512 * 1024 headers = { 'Content-Type': 'application/octet-stream' } fileobj = open(fp, 'rb') filename = os.path.basenam...Show MorePublished Nov 05, 2015View ContributorsVersion 1.0
Maverick_80689NimbostratusMar 18, 2016Thanks Jason, please ignore my previous comment. It works with version 11.5.1, just needed to adjust permissions on the destination folder.