File Upload via iControl REST Code : def _upload(host, creds, fp): chunk_size = 512 * 1024 headers = { 'Content-Type': 'application/octet-stream' } fileobj = open(fp, 'rb') filename = os.path.basenam...Show MorePublished Nov 05, 2015View ContributorsVersion 1.0
JRahmAdminMar 02, 2016I tested on 12.0, It's possible 11.6 might work, but I don't think the building blocks were in place.